Modelica.Thermal.FluidHeatFlow.Examples

Examples that demonstrate the usage of the FluidHeatFlow components

Information

This package contains test examples:

SimpleCooling: heat is dissipated through a media flow
ParallelCooling: two heat sources dissipate through merged media flows
IndirectCooling: heat is dissipated through two cooling cycles
PumpAndValve: demonstrates usage of an IdealPump and a Valve
PumpDropOut: demonstrates shutdown and restart of a pump
ParallelPumpDropOut: demonstrates shutdown and restart of a pump in a parallel circuit
OneMass: cooling of a mass (thermal capacity) by a coolant flow
TwoMass: cooling of two masses (thermal capacities) by two parallel coolant flows

Extends from Modelica.Icons.ExamplesPackage (Icon for packages containing runnable examples).

Package Content

Name	Description
SimpleCooling	Example: simple cooling circuit
ParallelCooling	Example: cooling circuit with parallel branches
IndirectCooling	Example: indirect cooling circuit
PumpAndValve	Example: cooling circuit with pump and valve
PumpDropOut	Example: cooling circuit with drop out of pump
ParallelPumpDropOut	Example: cooling circuit with parallel branches and drop out of pump
OneMass	Example: cooling of one hot mass
TwoMass	Example: cooling of two hot masses
Utilities	Utility models for examples

Modelica.Thermal.FluidHeatFlow.Examples.SimpleCooling

Example: simple cooling circuit

Information

1st test example: SimpleCooling

A prescribed heat source dissipates its heat through a thermal conductor to a coolant flow. The coolant flow is taken from an ambient and driven by a pump with prescribed mass flow.
Results:

output	explanation	formula	actual steady-state value
dTSource	Source over Ambient	dtCoolant + dtToPipe	20 K
dTtoPipe	Source over Coolant	Losses / ThermalConductor.G	10 K
dTCoolant	Coolant's temperature increase	Losses * cp * massFlow	10 K

Extends from Modelica.Icons.Example (Icon for runnable examples).

Parameters

Name	Description
medium	Cooling medium
TAmb	Ambient temperature [K]

Modelica.Thermal.FluidHeatFlow.Examples.ParallelCooling

Example: cooling circuit with parallel branches

Information

2nd test example: ParallelCooling

Two prescribed heat sources dissipate their heat through thermal conductors to coolant flows. The coolant flow is taken from an ambient and driven by a pump with prescribed mass flow, then split into two coolant flows connected to the two heat sources, and afterwards merged. Splitting of coolant flows is determined by pressure drop characteristic of the two pipes.
Results:

output	explanation	formula	actual steady-state value
dTSource1	Source1 over Ambient	dTCoolant1 + dTtoPipe1	15 K
dTtoPipe1	Source1 over Coolant1	Losses1 / ThermalConductor1.G	5 K
dTCoolant1	Coolant's temperature increase	Losses * cp * totalMassFlow/2	10 K
dTSource2	Source2 over Ambient	dTCoolant2 + dTtoPipe2	30 K
dTtoPipe2	Source2 over Coolant2	Losses2 / ThermalConductor2.G	10 K
dTCoolant2	Coolant's temperature increase	Losses * cp * totalMassFlow/2	20 K
dTmixedCoolant	mixed Coolant's temperature increase	(dTCoolant1+dTCoolant2)/2	15 K

Extends from Modelica.Icons.Example (Icon for runnable examples).

Parameters

Name	Description
medium	Cooling medium
TAmb	Ambient temperature [K]

Modelica.Thermal.FluidHeatFlow.Examples.IndirectCooling

Example: indirect cooling circuit

Information

3rd test example: IndirectCooling

A prescribed heat sources dissipates its heat through a thermal conductor to the inner coolant cycle. It is necessary to define the pressure level of the inner coolant cycle. The inner coolant cycle is coupled to the outer coolant flow through a thermal conductor.
Inner coolant's temperature rise near the source is the same as temperature drop near the cooler.
Results:

output	explanation	formula	actual steady-state value
dTSource	Source over Ambient	dtouterCoolant + dtCooler + dTinnerCoolant + dtToPipe	40 K
dTtoPipe	Source over inner Coolant	Losses / ThermalConductor.G	10 K
dTinnerColant	inner Coolant's temperature increase	Losses * cp * innerMassFlow	10 K
dTCooler	Cooler's temperature rise between inner and outer pipes	Losses * (innerGc + outerGc)	10 K
dTouterColant	outer Coolant's temperature increase	Losses * cp * outerMassFlow	10 K

Extends from Modelica.Icons.Example (Icon for runnable examples).

Parameters

Name	Description
outerMedium	Outer medium
innerMedium	Inner medium
TAmb	Ambient temperature [K]

Modelica.Thermal.FluidHeatFlow.Examples.PumpAndValve

Example: cooling circuit with pump and valve

Information

4th test example: PumpAndValve

The pump is running with half speed for 0.4 s, afterwards with full speed (using a ramp of 0.1 s).
The valve is half open for 0.9 s, afterwards full open (using a ramp of 0.1 s).
You may try to:

drive the pump with variable speed and let the valve full open to regulate the volume flow rate of coolant
drive the pump with constant speed and throttle the valve to regulate the volume flow rate of coolant

Extends from Modelica.Icons.Example (Icon for runnable examples).

Parameters

Name	Description
medium	Cooling medium
TAmb	Ambient temperature [K]

Modelica.Thermal.FluidHeatFlow.Examples.PumpDropOut

Example: cooling circuit with drop out of pump

Information

5th test example: PumpDropOut

Same as 1st test example, but with a drop out of the pump:
The pump is running for 0.2 s, then shut down (using a ramp of 0.2 s) for 0.2 s, then started again (using a ramp of 0.2 s).

Extends from Modelica.Icons.Example (Icon for runnable examples).

Parameters

Name	Description
medium	Cooling medium
TAmb	Ambient temperature [K]

Modelica.Thermal.FluidHeatFlow.Examples.ParallelPumpDropOut

Example: cooling circuit with parallel branches and drop out of pump

Information

6th test example: ParallelPumpDropOut

Same as 2nd test example, but with a drop out of the pump:
The pump is running for 0.2 s, then shut down (using a ramp of 0.2 s) for 0.2 s, then started again (using a ramp of 0.2 s).

Extends from Modelica.Icons.Example (Icon for runnable examples).

Parameters

Name	Description
medium	Cooling medium
TAmb	Ambient temperature [K]

Modelica.Thermal.FluidHeatFlow.Examples.OneMass

Example: cooling of one hot mass

Information

7th test example: OneMass

A thermal capacity is coupled with a coolant flow. Different initial temperatures of thermal capacity and pipe's coolant get ambient's temperature, the time behaviour depending on coolant flow.

Extends from Modelica.Icons.Example (Icon for runnable examples).

Parameters

Name	Description
medium	Cooling medium
TAmb	Ambient temperature [K]
TMass	Initial temperature of mass [K]

Modelica.Thermal.FluidHeatFlow.Examples.TwoMass

Example: cooling of two hot masses

Information

8th test example: TwoMass

Two thermal capacities are coupled with two parallel coolant flow. Different initial temperatures of thermal capacities and pipe's coolants get ambient's temperature, the time behaviour depending on coolant flow.

Extends from Modelica.Icons.Example (Icon for runnable examples).

Parameters

Name	Description
medium	Cooling medium
TAmb	Ambient temperature [K]
TMass1	Initial temperature of mass1 [K]
TMass2	Initial temperature of mass2 [K]

Automatically generated Tue Apr 05 09:37:03 2016.